Write a program to check whether the inputted number is an Armstrong number or not (the number can have any number of digits).

 #include <stdio.h>

#include <math.h>

#include <conio.h>

int main()

{

int num, i=1, power=0, isArm;

printf("Enter a number: ");

scanf("%d", &num);

//to calculate the length of the inputed num

while (num/i) {

i*=10;

power++;

}

i = num;

while (i>0) {

isArm += pow(i%10, power);

i /= 10;

}

if (num == isArm)

{

printf("%d is a armstrong number.", num);

}

else {

printf("%d is not a armstrong number.", num);

}

getch();

return 0;

}

/*

some armstrong numbers

1> 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

3> 153, 370, 371, 407

4> 1634, 8208, 9474

5> 54748, 92727, 93084

6> 548834

7> 1741725, 4210818, 9800817, 9926315

8> 24678050, 24678051, 88593477

9> 146511208, 472335975, 534494836, 912985153

*/